Welcome to the blog! Hey! This is a quick test post to verify that everything’s in working order. iℏ∂∂tψ=−ℏ22m∂2∂x2ψ+V(x)ψi\hbar \frac{\partial}{\partial t}\psi = \frac{-\hbar^2}{2m} \frac{\partial^2}{\partial x^2}\psi + V(x)\psiiℏ∂t∂ψ=2m−ℏ2∂x2∂2ψ+V(x)ψ